Trying operator of equation and relationship operator

Guide:

1. Use steps program II, but using Project_name which differing, for example Third Program


2. Change block program function play with following:
   

   int num1; /* first number to be read from user */
   int num2; /* second number to be read from user */
   
   printf( "Enter two integers, and I will tell you\n" );
   printf( "the relationships they satisfy: " );

   scanf( "%d%d", &num1, &num2 ); /* read two integers */
   
   
   if ( num1 == num2 ) {
   printf( "%d is equal to %d\n", num1, num2 );
   } /* end if */

   if ( num1 != num2 ) {
   printf( "%d is not equal to %d\n", num1, num2 );
   } /* end if */

   if ( num1 < num2 ) {
   printf( "%d is less than %d\n", num1, num2 );
   } /* end if */

   if ( num1 > num2 ) {
   printf( "%d is greater than %d\n", num1, num2 );
   } /* end if */

   if ( num1 <= num2 ) {
   printf( "%d is less than or equal to %d\n", num1, num2 );
   } /* end if */

   if ( num1 >= num2 ) {
   printf( "%d is greater than or equal to %d\n", num1, num2 );
   } /* end if */

   return 0; /* indicate that program ended successfully */